Voltage Drop Calculator
Free voltage drop calculator for Australian sparkies. Check 5% compliance for any cable size, length, and load per AS/NZS 3008.1.1:2025.
Inputs
▶Advanced options
AS/NZS 3000:2018 default limit is 5%
Aluminium has higher resistance for the same size
Design current is shared equally across the cables
Uses Vd = I x L x [K x (R cosθ + X sinθ)]. Matters on cables 35 mm² and above. Not applied to DC.
Results
Voltage Drop
6.62
V
2.9%
of 230V
Voltage Drop
2.9 % (<= 5 %)
Minimum Voltage at Load
223.38 V (>= 216.2 V)
Show the working
| Step | Working | Result | Reference |
|---|---|---|---|
| Design current (Ib) | Ib = 20 A over 30 m at 230 V, limit 5% | 20 A | Input |
| Cable size and resistance, 4mm² | Table lookup: 4 mm2 copper at 75 C = 5.5200 mohm/m | 5.5200 mΩ/m | AS/NZS 3008.1.1:2025 Table 30 PLACEHOLDER |
| Phase multiplier, 1-phase-ac | 1-phase-ac: K = 2 (current flows out and back) | 2.000 | 2 for 1-phase / DC |
| Voltage drop (ΔV) | 20 A x 5.5200 mohm/m x 30 m x 2.000 / 1000 = 6.62 V | 6.62 V | ΔV = (Ib × R × L × K) / 1000 |
| Voltage drop percentage | 6.62 V / 230 V x 100 = 2.9% (limit 5%, headroom 2.1%) | 2.9 % | AS/NZS 3000:2018 Cl. 3.6 |
| Voltage at load | 230 V - 6.62 V = 223.38 V (minimum allowed 216.20 V) | 223.38 V | Nominal - drop |
Standards referenced
- AS/NZS 3008.1.1:2025 Table 30. Conductor DC resistance at 75°C for copper and aluminium
- AS/NZS 3000:2018 Clause 3.6. Voltage drop in consumer mains and sub-mains (5% limit)
- AS/NZS 3000:2018. Supply voltage must not fall below 94% of nominal
Lookup values used by these calculators are indicative and awaiting validation against the current standards. Confirm against your own licensed copy before relying on a result for design.
Parameters
Every field on the form, what it means, the range the form accepts, and the traps worth knowing before you trust the number.
- Phase configurationsingle phase, three phase, or DC
- Selects the multiplier applied to the run length. Single phase and DC use a factor of 2, because the current travels out along the active and back along the neutral or negative. Three phase uses 1.732, the square root of 3, because the return path is shared between phases. Changing this selector also resets the nominal voltage to 230, 400 or 48 volts.
- Nominal voltagevolts
- The declared supply voltage the drop is measured against. It is set automatically by the phase selector: 230 volts for single phase, 400 volts line to line for three phase, and 48 volts for DC. The percentage result is the drop divided by this number, so a three phase result is expressed against the line-to-line voltage, not the phase voltage.
- Load currentamps, 0.1 to 500
- The design current of the circuit, the current the cable actually carries. Use the calculated load current, not the protective device rating. Sizing a 20 amp breaker onto a circuit that draws 8 amps and entering 20 amps here will overstate the drop by a factor of two and a half.
- Cable run lengthmetres, 1 to 2000
- The one-way route length from the source to the load. Do not double it for the return conductor. The calculator applies the return path itself through the phase multiplier, so entering the total there-and-back length will double the answer. Use the routed length including vertical drops and risers, not the straight-line distance on the plan.
- Cable sizesquare millimetres, 1.5 to 300
- The cross-sectional area of one active conductor. Standard sizes only: 1.5, 2.5, 4, 6, 10, 16, 25, 35, 50, 70, 95, 120, 150, 185, 240 and 300. This calculator validates a size you have already chosen. If you want the calculator to pick the size for you, use the cable sizing calculator instead.
- Maximum voltage droppercent, 0.1 to 10, default 5
- Found under advanced options. The compliance target the result is graded against. AS/NZS 3000:2018 Clause 3.6 uses 5 percent for the whole installation. Tighten it to 3 percent or less when you are budgeting a submain and need to leave headroom for the final subcircuits downstream.
- Conductor materialcopper or aluminium
- Selectable under advanced options. Aluminium has a higher resistance for the same cross-sectional area, so the same run will show a larger drop.
Assumptions and limits
This is a resistive voltage drop check. Knowing exactly what it leaves out is the difference between using it well and being caught out by it.
What the calculator assumes
- Resistance only, no reactance. The calculation is load current times resistance times length times the phase factor, divided by 1000. Inductive reactance is not included at all. For conductors of 35 square millimetres and above, and for single-core cables installed spaced, reactance is a real share of the total impedance, so the answer here will read low.
- No power factor term. The engine defines a power factor field but never uses it. Every load is treated as though the drop is purely resistive. A motor at 0.8 power factor on a large conductor will drop more in reality than this figure suggests.
- Copper resistance at 75 degrees Celsius. One fixed resistance value per size, regardless of insulation type or how lightly the cable is loaded. A cable running well below its rating sits cooler and has lower resistance, so the calculator is conservative in that direction.
- One cable, one segment. No parallel conductors, no grouping, no ambient temperature correction, no harmonics, no neutral current in an unbalanced three phase system.
- Two checks are run. Drop as a percentage against your target, and voltage at the load against 94 percent of nominal. The percentage is rounded to one decimal place before it is compared, so a true 5.04 percent displays as 5.0 percent and reads as a pass. Treat anything within about a tenth of a percent of the limit as needing a second look.
What this should not be used for
- Final design sign-off on any conductor of 35 square millimetres or larger, where the missing reactance term matters.
- Solar photovoltaic string and inverter circuits, where the concern is voltage rise rather than drop. Use the voltage rise calculator.
- Motor starting voltage dip, which is a transient at locked-rotor current, not a steady-state drop.
- Whole-of-installation budgeting on its own. The 5 percent allowance runs from the point of supply to the most remote point, so mains, submains and final subcircuits all share it. This tool checks one segment at a time.
- Aluminium conductors, which the web form cannot select.
The resistance values behind this calculator are indicative figures for the conductor sizes listed. They have not been transcribed from a licensed copy of AS/NZS 3008.1.1 and have not been validated by a chartered professional engineer. Check every result against the current edition of AS/NZS 3008.1.1 and AS/NZS 3000, and have the responsible person for the installation sign off the final design.
Worked examples
Three runs through the same arithmetic the calculator performs, so you can check the tool against a hand calculation and see where the answer comes from.
Example 1: single phase submain to a shed, 4 square millimetres over 30 metres
A 230 volt single phase submain feeds a detached shed 30 metres from the switchboard. The load draws 20 amps. The installer has 4 square millimetre copper on the van and wants to know whether it will hold the 5 percent limit.
| Phase configuration | Single phase |
|---|---|
| Nominal voltage | 230 V |
| Load current | 20 A |
| Run length (one way) | 30 m |
| Cable size | 4 mm² |
| Maximum voltage drop | 5 % |
Step 1. Look up the conductor resistance for 4 square millimetre copper at 75 degrees Celsius: 5.52 milliohms per metre.
Step 2. Single phase, so the phase multiplier is 2.
Step 3. Voltage drop equals 20 times 5.52 times 30 times 2, divided by 1000, which is 6.62 volts.
Step 4. As a percentage: 6.62 divided by 230, times 100, equals 2.9 percent.
Step 5. Voltage at the load: 230 minus 6.62 equals 223.38 volts. The absolute floor is 94 percent of 230, which is 216.2 volts.
PASS. 2.9 percent against a 5 percent limit leaves 2.1 percent of margin, and 223.38 volts at the load clears the 216.2 volt floor. The permitted drop in volts is 11.5, and this run uses 6.62 of it.
Example 2: three phase submain, 25 square millimetres over 85 metres
A commercial fit-out runs a 400 volt three phase submain 85 metres from the main switchboard to a remote distribution board. Design current is 63 amps. The conductor proposed is 25 square millimetre copper.
| Phase configuration | Three phase |
|---|---|
| Nominal voltage | 400 V |
| Load current | 63 A |
| Run length (one way) | 85 m |
| Cable size | 25 mm² |
| Maximum voltage drop | 5 % |
Step 1. Resistance for 25 square millimetre copper at 75 degrees Celsius: 0.868 milliohms per metre.
Step 2. Three phase, so the multiplier is 1.732, the square root of 3.
Step 3. Voltage drop equals 63 times 0.868 times 85 times 1.732, divided by 1000, which is 8.05 volts.
Step 4. As a percentage: 8.05 divided by 400, times 100, equals 2.0 percent.
Step 5. Voltage at the load: 400 minus 8.05 equals 391.95 volts, against a floor of 376 volts.
PASS at 2.0 percent, with 3.0 percent of margin left over. That headroom matters: the submain has only consumed 2 percent of the 5 percent budget, leaving 3 percent for every final subcircuit fed from the remote board.
Example 3: a run that fails, and what fixes it
A 20 amp final subcircuit is run 60 metres in 2.5 square millimetre copper on 230 volts single phase. This is the classic long-run mistake.
| Phase configuration | Single phase |
|---|---|
| Nominal voltage | 230 V |
| Load current | 20 A |
| Run length (one way) | 60 m |
| Cable size | 2.5 mm² |
| Maximum voltage drop | 5 % |
Step 1. Resistance for 2.5 square millimetre copper: 8.87 milliohms per metre.
Step 2. Voltage drop equals 20 times 8.87 times 60 times 2, divided by 1000, which is 21.29 volts.
Step 3. As a percentage: 21.29 divided by 230, times 100, equals 9.3 percent. The compliance margin is negative 4.3 percent.
Step 4. Voltage at the load: 230 minus 21.29 equals 208.71 volts, which is below the 216.2 volt floor.
FAIL on both checks. The drop is 9.3 percent against a 5 percent limit, and the load sits at 208.71 volts.
Step 5, the fix. Step up to 4 square millimetres, resistance 5.52: the drop becomes 20 times 5.52 times 60 times 2 divided by 1000, which is 13.25 volts, or 5.8 percent. Still a fail.
Step 6. Step up again to 6 square millimetres, resistance 3.69: the drop becomes 20 times 3.69 times 60 times 2 divided by 1000, which is 8.86 volts, or 3.9 percent, and the load sits at 221.14 volts.
PASS at 6 square millimetres. Note that the current rating of 2.5 square millimetre cable would have been perfectly adequate for 20 amps in many installation methods. Over 60 metres it is voltage drop, not current rating, that forces the size up by two steps.
Voltage Drop Guide for AS/NZS 3000:2018
Voltage drop is the reduction in voltage along a cable run caused by the resistance and reactance of the conductor. Every cable carrying current will drop some voltage between its supply end and its load end. If the voltage at the load is too low, equipment may malfunction, motors may overheat or stall, and lighting may dim or flicker. AS/NZS 3000:2018 Clause 3.6 sets a maximum allowable voltage drop of 5% from the point of supply to the most remote point of the installation. This calculator determines whether a given cable size, length, and load current combination stays within that limit.
Key concepts
- The voltage drop formula. The general form is voltage drop equals I x L x (R x cos phi + X x sin phi), where I is load current in amps, L is the route length, R and X are the per-metre resistance and reactance, and cos phi is the load power factor. By default this calculator uses the resistive form, I x R x L, with a factor of 2 for the return path on single phase and DC, or 1.732 for three phase. Tick Include reactance under advanced options and it applies the full expression with your load power factor.
- When voltage drop governs cable size. For short cable runs (under approximately 30 metres), the current carrying capacity of the cable almost always determines the minimum size. For longer runs, particularly on circuits with high load currents, voltage drop becomes the binding constraint and may force a cable one or two sizes larger than what current rating alone would require. Knowing which constraint governs saves material cost on short runs and prevents compliance failures on long runs.
- Reactance in larger cables. For cables 35 mm squared and above, the inductive reactance (X) becomes a meaningful component of the total impedance. Ignoring reactance on large cables underestimates voltage drop and may lead to a cable selection that fails compliance at full load. Tick Include reactance under advanced options for those runs, then set the load power factor and the cable construction. Single-core conductors sit further apart than multi-core, which raises reactance further.
- The 5% limit is cumulative. The 5% limit applies from the point of supply (typically the meter or main switchboard) to the most remote outlet on the installation. This means the voltage drop on each segment of the wiring system (mains, submains, final subcircuits) must be considered together. A submain consuming 3% of the budget leaves only 2% for the final subcircuit.
Common scenarios
- Running a long final subcircuit to a shed or granny flat. A 2.5 mm squared cable supplying a 20 A circuit over a 50-metre run will likely exceed the 5% voltage drop limit. The electrician enters the cable size, run length, and load current to check compliance. If the drop is too high, the calculator determines whether upsizing to 4 mm squared or 6 mm squared brings the installation within limits. This is one of the most common voltage drop problems in residential work.
- Sizing a submain from the main switchboard to a sub-distribution board. In a commercial fit-out, the submain may run 80 to 120 metres from the main switchboard to a remote distribution board. The electrician needs to size the submain so that the voltage drop on the submain itself leaves enough voltage drop budget for the final subcircuits downstream. The calculator helps balance the submain and subcircuit voltage drop allocation.
- Checking voltage drop on a motor circuit with low power factor. Motors typically operate at power factors between 0.75 and 0.90, which increases the reactive component of voltage drop compared to a resistive load. The electrician enters the motor FLC and power factor to see the actual voltage drop, which will be higher than a unity power factor load on the same cable. This is especially important for long motor runs where the combined effect of distance and low power factor can push the voltage drop well beyond 5%.
Common questions
What is the maximum voltage drop allowed in AS/NZS 3000?+
AS/NZS 3000:2018 Clause 3.6 caps voltage drop at 5 percent of the nominal supply voltage measured from the point of supply to the most remote point of the installation. For 230 V single-phase that is 11.5 V; for 400 V three-phase line-to-line that is 20 V. Many supply authorities and sensitive equipment specifications tighten this to 3 percent. The calculator lets you set the target percentage and reports the compliance margin for the cable size you choose.
How is voltage drop calculated for an Australian cable run?+
Voltage drop in volts equals I times L times (R times cos phi plus X times sin phi). I is the load current, L is the route length in metres (one-way for single-phase, multiplied by the line-to-line factor for three-phase), R and X are the cable per-metre resistance and reactance, and cos phi is the load power factor. This calculator implements both forms. By default it uses the resistive term only. Tick Include reactance under advanced options and it applies the full Clause 4.5 expression with your load power factor and the cable reactance, using the factor of 2 for single phase or the square root of 3 for three phase. Reactance is not applied to DC circuits, where it does not exist.
When does voltage drop become the binding constraint instead of current rating?+
For runs under about 30 metres voltage drop is rarely the binding constraint; current carrying capacity sets the cable size. For longer runs, especially low-voltage circuits with high load currents, voltage drop dominates and forces a larger cable than current rating alone would require. This calculator checks voltage drop only. To see which of the two constraints governs a given circuit, use the cable sizing calculator, which runs both.
How do I include reactance for large high-current cables?+
For cables 35 mm squared and larger, reactance (X) becomes a meaningful share of the impedance and should be included alongside resistance. Tick Include reactance under advanced options and the calculator applies it, taking the reactance for the selected size and your load power factor. Single-core construction raises reactance relative to multi-core and there is a selector for it. For cables under 25 mm squared reactance is negligible and the resistive default is a close approximation.
Does the calculator handle three-phase voltage drop?+
Yes. Select three-phase in the inputs and the calculator applies the line-to-line correction factor to the route length and works in line-to-line voltage for compliance checking. Both balanced and unbalanced loads can be modelled by entering the worst-phase current.
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