AS/NZS 61000.3.100

Power Factor Correction Calculator

Calculate capacitor bank size to correct power factor per AS/NZS 61000.3.100.

Inputs

Peak demand kW from the meter or a logger

Measured displacement PF (0.1 to 0.99)

Distributors typically require 0.9 or better

Supply Phase

>Staged (automatic) bank

Steps default to enough to cover the requirement

Alone, splits the standard bank into equal steps

>Capacitor hardware (AS/NZS 3000 Cl 4.15)

Gives capacitance, rated current, conductor rating and switching device

>Harmonic resonance and detuning

From the distributor or a fault study. Overrides the transformer estimate

From the nameplate, typically 4 to 6 %

For example 7 (189 Hz on 50 Hz). Default 7 for the recommendation

>Feeder losses and energy

Resistance of one active conductor from source to load

>Tariff and payback

From your network tariff

>Light load (over-correction check)

Nights, weekends, shutdowns

Default: the current power factor

Results

Required Capacitor Bank

60

kvar

(55.32 kvar required)

Current kVA

133.33

PF 0.75

Corrected kVA

105.26

PF 0.95

Current reduction (at target PF)21.1%
Reactive power before88.19 kvar
Reactive power at target32.87 kvar

Checks

  • PassTarget Power Factor: 0.9500 (min 0.90)

    Distributor connection requirements (0.90 minimum is typical)

  • PassCapacitor Sizing: 60 kVAR (min 55.32)

    Standard bank size series (indicative)

Show the working
Step by step derivation of the result
StepWorkingResultReference
Calculate current power factor anglephi1 = acos(0.75) = 0.722734 rad (41.41 deg)0.722734 radPower triangle (first principles)
Calculate target power factor anglephi2 = acos(0.95) = 0.317560 rad (18.19 deg)0.317560 radPower triangle (first principles)
Calculate current reactive powerQ1 = 100 kW x tan(0.7227) = 100 x 0.8819 = 88.19 kVAR88.19 kVARPower triangle (first principles)
Calculate target reactive powerQ2 = 100 kW x tan(0.3176) = 100 x 0.3287 = 32.87 kVAR32.87 kVARPower triangle (first principles)
Calculate required reactive power compensationQc = 88.19 kVAR - 32.87 kVAR = 55.32 kVAR55.32 kVARPower triangle (first principles)
Calculate current apparent powerS1 = 100 kW / 0.75 = 133.33 kVA133.33 kVAPower triangle (first principles)
Calculate corrected apparent powerS2 = 100 kW / 0.95 = 105.26 kVA105.26 kVAPower triangle (first principles)
Calculate current saving percentage(1 - 0.75 / 0.95) x 100 = 21.05%21.05 %Power triangle (first principles)
Round to standard capacitor bank sizeStandard size lookup: 55.32 kVAR against 5/10/15/20/25/30/40/50/60/75/100/125/150/200/250/300/400/500 kVAR gives 60 kVAR60 kVARStandard bank size series (indicative)

Standards referenced

  • AS/NZS 61000.3.100. Power quality and compatibility with supply

Where a lookup value is marked indicative, it has not been transcribed from the current edition of the standard. Check results against your own copy before relying on them for design.

Important: These results are indicative only. Check the design against AS/NZS 3000 Clause 4.15, your distributor's connection requirements and a site harmonic assessment, and have it signed off by the person responsible for the installation.

Parameters

Seven fields are always on the form, and fourteen more sit in collapsed sections for staging, capacitor hardware, harmonic resonance, feeder losses, tariff and light load. Every optional field is blank by default, and leaving them all blank gives exactly the basic bank sizing. Each one, once entered, changes a result, a check, a warning or a step in the working.

Active power
The real power the installation draws, in kilowatts. Form range 1 to 10000, default 100. Every kilovolt-ampere reactive figure scales directly with it, so it is the single most important input on the page. Take it from a demand meter, a power quality logger or the sum of connected loads with diversity applied. Gotcha. Use the kilowatts that coincide with the power factor you enter, ideally a peak demand interval. A yearly average kilowatt figure paired with a worst case power factor will size a bank that overcorrects for most of the year.
Current power factor
The measured, uncorrected power factor. Dimensionless, form range 0.1 to 0.99, default 0.75. Typical uncorrected values are 0.65 to 0.80 for a motor-heavy factory, 0.80 to 0.90 for a commercial building with chillers and air handling, and above 0.95 where loads are largely resistive. Gotcha. Use a measured value, not a nameplate one. Also be aware whether your meter reports displacement power factor or true power factor. On a site with drives and switching supplies the two differ, and capacitors correct only the displacement component. Correcting to a true power factor target with capacitors alone will not work.
Target power factor
The power factor you want after correction. Dimensionless, form range 0.9 to 0.99, default 0.95. Most Australian distributors set 0.90 as the threshold below which demand penalties apply, so 0.95 is a common target because it leaves margin. Gotcha. Do not chase unity. The kilovolt-ampere reactive required climbs steeply above about 0.97 for very little further reduction in apparent power, and a fixed bank sized to unity at peak will push the site leading at light load, which raises voltage and can be penalised in its own right. Entering a target below the current power factor produces a negative requirement, which the tool clamps to zero.
Supply voltage
Selectable as 230, 400, 415 or 11000 V. Gotcha. The required kilovolt-amperes reactive is independent of voltage, so it is the same at 400 V as at 11 kV. Voltage matters to the hardware: once you choose a capacitor connection it sets the capacitance in microfarads, the bank rated current and the AS/NZS 3000 discharge period, and with a feeder resistance it sets the line current and losses.
Supply phase
Single phase or three phase. Gotcha. The total kilovolt-amperes reactive required is a whole-of-supply figure either way. Phase matters for the rated current (divided by root 3 times the line voltage on three phase, by the voltage on single phase), for the capacitance per phase and for feeder losses, which count three conductors on three phase and two on single phase.
Frequency
Selectable as 50 Hz or 60 Hz. Gotcha. Frequency sets the detuning frequency, the supply frequency divided by the square root of the reactor fraction. A 7 per cent reactor tunes to 189 Hz on 50 Hz and 227 Hz on 60 Hz. Earlier versions of this tool reported 189 Hz on both, which was wrong on 60 Hz and is now corrected. Frequency also sets the capacitance in microfarads and the resonance frequency in hertz.
Significant harmonics
A checkbox for sites with variable speed drives, rectifiers or large switching power supplies. Ticking it turns on a detuning recommendation when the required compensation exceeds 20 kilovolt-amperes reactive. Gotcha. On its own it is a yes or no flag, not a harmonic study. Enter a fault level or transformer details below to get an actual resonance order. A resonance close to a characteristic harmonic turns the detuning recommendation on whether or not this box is ticked.
Step size and number of steps
Optional, in kilovolt-amperes reactive and a whole number of 1 to 24. Enter a step size and the tool uses enough steps to cover the requirement, or the number you give. Enter only a number of steps and the standard bank is split equally. The result shows the power factor with each step switched in, models an automatic controller that switches in the fewest steps that reach your target without going leading, and adds a staged capacity check and a full-load power factor check. Gotcha. The controller model is simple. A real relay has a response band (C/k setting), switching delays and step rotation, so treat the step chosen as indicative.
Capacitor connection
Optional, delta or star. Choosing one gives the capacitance per phase in microfarads (delta: Q divided by 3 times 2 pi f times V squared; star: Q divided by 2 pi f times V squared, three times the delta value), the rated current of the bank and of each step, and the AS/NZS 3000 Clause 4.15 requirements: conductors rated not less than 135 per cent of the capacitor rated current (Clause 4.15.2.3), contactor and fuse control permitted only for capacitors of not more than 100 kVAr and otherwise a circuit-breaker with an overcurrent release (Clause 4.15.3.3), and discharge to 50 V within 1 minute up to 650 V or 5 minutes above (Clause 4.15.3.1). Gotcha. On a fixed bank the tool applies the 100 kVAr test to the whole bank. A bank built from smaller units may qualify unit by unit, so check the actual make-up. The conductor figure must also be not less than the circuit-breaker setting where one is used.
Fault level, transformer rating and impedance
Optional. Enter the fault level at the bank in MVA, or a transformer rating in kVA with its impedance in per cent (1 to 20), which estimates the fault level as kVA divided by the impedance fraction. The tool then gives the parallel resonance order h, the square root of fault level over bank kvar, for the full bank and for every switching stage, and checks that the worst stage is at least 10 per cent (indicative) away from the 5th, 7th, 11th and 13th harmonics. Gotcha. The transformer estimate assumes an infinite source upstream, so it overstates the fault level and the resonance order. Running on a generator or with an alternate supply lowers the fault level and moves the resonance down.
Detuning reactor
Optional, per cent of capacitor reactance (1 to 20), for example 7. It sets the detuning frequency, gives the tuning order 1 divided by the square root of the reactor fraction, checks that it sits below the 5th harmonic, and gives the capacitor voltage raised by the reactor, the supply voltage divided by one minus the fraction. Entering it replaces the undetuned resonance check. Gotcha. A 7 per cent reactor on 400 V raises the capacitor voltage to about 430 V before harmonics, so the capacitors need a higher voltage rating than the supply.
Feeder resistance, operating hours and energy price
Optional. The resistance of one active conductor of the feeder in ohms gives the line current before and after correction and the I squared R loss saving. Operating hours turn that into kilowatt hours a year, and the energy price turns it into dollars. Gotcha. This is the only part of the energy bill that correction reduces, and it is usually small. Hours and price do nothing without a resistance, and the tool says so.
Demand charge and bank cost
Optional. A demand charge in dollars per kVA per month gives the monthly and yearly saving from the reduced kVA demand at full load with the bank as installed. A bank cost gives a simple payback against the demand and energy savings. Gotcha. Network tariffs differ. Some bill the peak kVA in a rolling window, some bill kW with a power factor penalty, and some do not bill demand at all. Check yours before trusting the payback.
Minimum load and its power factor
Optional. The light-load kW (nights, weekends, shutdowns) and its lagging power factor, which defaults to the current power factor. The tool works out the reactive demand at that load and the power factor with the bank in: a fixed bank stays fully in, a stepped bank switches out to the fewest steps that reach your target. A check fails if the site is driven leading. Gotcha. Light-load power factor is often worse than full load because motors run unloaded, so enter a measured value if you have one.

Assumptions and limits

What the tool assumes

  • Two operating points at most. A full-load point and, if you enter it, a minimum-load point. There is no full load profile. A stepped bank is modelled as an automatic panel that switches in the fewest steps reaching the target without going leading; a bank without steps is treated as fixed.
  • Purely displacement power factor. The maths is the standard trigonometric relationship, required kilovolt-amperes reactive equals active power multiplied by the difference between the tangent of the present phase angle and the tangent of the target phase angle. That relationship only holds for the fundamental. Harmonic distortion is not modelled anywhere in the numbers.
  • Lagging power factor throughout. Both power factors are treated as lagging and correction is always assumed to be capacitive. A site already leading is not handled.
  • The bank rounds up to a standard size. The selection comes from the series 5, 10, 15, 20, 25, 30, 40, 50, 60, 75, 100, 125, 150, 200, 250, 300, 400 and 500 kilovolt-amperes reactive, always choosing the first entry at or above the requirement. That deliberately overcorrects, sometimes by a lot on small requirements. Enter a minimum load to see whether the bank drives the site leading at light load.
  • The current saving figure is a current reduction, not money. It is one minus the ratio of the two power factors, expressed as a percentage. It is the percentage reduction in apparent power and therefore in line current. It is not a reduction in your energy bill, because kilowatt hours do not change. Enter a demand charge, and a feeder resistance with hours and an energy price, to get dollar figures.
  • Hardware is sized, not designed. With a connection chosen you get capacitance, rated current, the Clause 4.15.2.3 minimum conductor rating and the Clause 4.15.3.3 control device. There is no cable selection, no protection setting, no thyristor switching, no enclosure or ventilation design and no harmonic filter design.
  • Resonance is a screening estimate. The order h equals the square root of fault level over bank kvar, the classic parallel resonance between the bank and the supply inductance. It ignores load damping, other capacitance on the network and cable capacitance. The 10 per cent margin is an indicative screening value, not a figure from a standard.

What the compliance checks actually check

Two checks always run. The first confirms your target power factor is at least 0.90, which is a check on what you typed rather than on the installation. The second confirms the standard bank is at least the required kilovolt-amperes reactive, which passes by construction unless the requirement exceeds 500 kilovolt-amperes reactive. The optional inputs add up to five more: staged bank capacity, full-load power factor reached with the steps switched in, resonance clear of the 5th, 7th, 11th and 13th harmonics (or, with a reactor, tuning below the 5th), and no over-correction at minimum load. None of them is a harmonic study.

What this must not be used for

  • Final capacitor bank design, including step sizing, switching scheme, controller settings, protection or the bank subcircuit.
  • Any decision about detuned reactors or harmonic filters. That requires a measured harmonic spectrum and a resonance study against the actual supply impedance.
  • Sites with significant harmonic distortion where true power factor rather than displacement power factor is the problem. Capacitors do not correct distortion power factor and can make it worse.
  • Estimating a financial payback. The current saving percentage is not a bill saving.
  • Correcting individual motors at the starter, which needs the motor's magnetising current so the capacitor does not self-excite the machine on coast down.
  • Evidence of compliance. This calculator is a design aid, not a certification. Check every result against the current edition of AS/NZS 61000.3.100, your distributor's connection requirements and a site harmonic assessment, and have it signed off by the person responsible for the installation.

Worked examples

Five examples. The first three use only the basic fields. The last two use the optional inputs: a staged bank with hardware, losses, tariff and light load, and a resonance screen with and without a detuned reactor. The tangent values below are the tangent of the arc cosine of each power factor, which is what the calculator computes internally.

Example 1. 100 kilowatt workshop corrected from 0.75 to 0.95

A light engineering workshop on a 400 V three-phase supply has a measured peak demand of 100 kW at 0.75 power factor. The distributor penalises below 0.90, so the target is 0.95. There are no significant drive loads.

Active power
100 kW
Current power factor
0.75
Target power factor
0.95
Supply
400 V, three phase
Harmonics
Not ticked

Present phase angle: arc cosine of 0.75 = 0.722734 radians, tangent = 0.881917

Target phase angle: arc cosine of 0.95 = 0.317560 radians, tangent = 0.328684

Present reactive power: 100 x 0.881917 = 88.19 kilovolt-amperes reactive

Target reactive power: 100 x 0.328684 = 32.87 kilovolt-amperes reactive

Required compensation: 88.19 minus 32.87 = 55.32 kilovolt-amperes reactive

Apparent power before: 100 divided by 0.75 = 133.33 kilovolt-amperes. After: 100 divided by 0.95 = 105.26 kilovolt-amperes.

Current reduction: (1 minus 0.75 divided by 0.95) x 100 = 21.05 per cent

Standard bank: first size at or above 55.32 is 60 kilovolt-amperes reactive

Result: a 60 kilovolt-ampere reactive bank against a 55.32 requirement. Target power factor at least 0.90, PASS. Capacitor sizing at least the requirement, PASS. Apparent demand falls from 133.33 to 105.26 kilovolt-amperes, which is 28 kilovolt-amperes of transformer and cable capacity handed back to the site.

Example 2. 250 kilowatt plant with drives, detuning triggered

A processing plant draws 250 kW at 0.82 power factor and runs a large number of variable speed drives. The target is again 0.95 and the harmonics box is ticked.

Active power
250 kW
Current power factor
0.82
Target power factor
0.95
Supply
415 V, three phase
Harmonics
Ticked

Present phase angle: arc cosine of 0.82, tangent = 0.698004

Present reactive power: 250 x 0.698004 = 174.50 kilovolt-amperes reactive

Target reactive power: 250 x 0.328684 = 82.17 kilovolt-amperes reactive

Required compensation: 174.50 minus 82.17 = 92.33 kilovolt-amperes reactive

Apparent power before: 250 divided by 0.82 = 304.88 kilovolt-amperes. After: 250 divided by 0.95 = 263.16 kilovolt-amperes.

Current reduction: (1 minus 0.82 divided by 0.95) x 100 = 13.68 per cent

Standard bank: first size at or above 92.33 is 100 kilovolt-amperes reactive

Detuning: the harmonics box is ticked and the requirement of 92.33 exceeds 20, so a detuned bank is recommended. With the default 7 per cent reactor the tuning point is 50 divided by the square root of 0.07 = 189 Hz

Result: a 100 kilovolt-ampere reactive bank against a 92.33 requirement. Both checks PASS. Take the detuning recommendation as a flag that a harmonic study is needed, not as a design. On a plant with this much drive load, the true power factor will be lower than the 0.82 displacement figure, and capacitors will not close that gap. Enter the transformer or fault level to screen for resonance, as in Example 5.

Example 3. Small single-phase site, and the round-up problem

A small single-phase 230 V site draws 15 kW at 0.90 power factor and wants 0.95 for margin. This example shows how the standard size series behaves when the requirement is small.

Active power
15 kW
Current power factor
0.90
Target power factor
0.95
Supply
230 V, single phase
Harmonics
Not ticked

Present phase angle: arc cosine of 0.90, tangent = 0.484322

Present reactive power: 15 x 0.484322 = 7.26 kilovolt-amperes reactive

Target reactive power: 15 x 0.328684 = 4.93 kilovolt-amperes reactive

Required compensation: 7.26 minus 4.93 = 2.33 kilovolt-amperes reactive

Apparent power before: 15 divided by 0.90 = 16.67 kilovolt-amperes. After: 15 divided by 0.95 = 15.79 kilovolt-amperes.

Current reduction: (1 minus 0.90 divided by 0.95) x 100 = 5.26 per cent

Standard bank: the smallest entry in the series is 5, so 5 kilovolt-amperes reactive is returned

Result: 2.33 kilovolt-amperes reactive required, 5 kilovolt-amperes reactive returned. Both checks PASS. Read that pass carefully. The returned bank is more than double the requirement, because 5 is the smallest standard size the tool knows about. Fitting 5 kilovolt-amperes reactive here would overcorrect this site into a leading power factor whenever the load drops below about half, which is most evenings. At this scale the honest conclusion is that a 5.26 per cent current reduction is unlikely to justify a bank at all. Enter a minimum load and the tool will flag the leading power factor for you.

Example 4. 400 kilowatt factory with a staged bank

A factory on 400 V three phase draws 400 kW at 0.80 power factor and targets 0.95. The bank is built from 50 kvar steps in delta, fed from a 1000 kVA 5 per cent transformer. The feeder has 0.01 ohm per conductor, the site runs 4000 hours a year at $0.25 per kWh, the demand charge is $12 per kVA per month, the bank costs $30,000, and the overnight load is 120 kW at 0.75.

Active power
400 kW
Power factor
0.80 to 0.95
Step size
50 kvar
Connection
Delta
Transformer
1000 kVA, 5%
Feeder
0.01 ohm per conductor
Tariff
$12/kVA/month, $0.25/kWh, 4000 h
Minimum load
120 kW at 0.75

Reactive power: 400 x 0.75 = 300.00 kvar now, 400 x 0.328684 = 131.47 kvar at target, so 168.53 kvar is required

Steps: 168.53 divided by 50, rounded up, is 4 steps, 200 kvar installed

Power factor with 1, 2, 3 and 4 steps in: 0.8480, 0.8944, 0.9363 and 0.9701. Three steps fall short of 0.95, so the controller needs all four.

After correction: 400 divided by the square root of (400 squared plus 100 squared) = 400 / 412.31 = 0.9701 lagging

Capacitance per phase in delta: 200,000 divided by (3 x 314.16 x 400 squared) = 1326.29 uF, or 331.57 uF per step

Rated current: 200,000 divided by (root 3 x 400) = 288.68 A for the bank, 72.17 A per step

Clause 4.15.2.3 conductors: 1.35 x 288.68 = 389.71 A for the bank, 1.35 x 72.17 = 97.43 A per step

Clause 4.15.3.3: each 50 kvar step is not more than 100 kVAr, so contactor and fuse control is permitted. Clause 4.15.3.1: discharge to 50 V within 1 minute.

Fault level: 1000 kVA / 0.05 = 20 MVA. Resonance order with 1 to 4 steps in: 20, 14.14, 11.55 and 10.00. With three steps in, 11.55 is 4.97 per cent from the 11th harmonic.

Line current: 500 kVA gives 721.69 A, 412.31 kVA gives 595.12 A. Loss in 3 conductors: 15.63 kW before, 10.62 kW after, a 5.00 kW saving, 20,000 kWh and $5000 a year.

Demand: (500 minus 412.31) = 87.69 kVA x $12 = $1052.27 a month, $12,627.28 a year

Payback: $30,000 divided by ($12,627.28 + $5000) = 1.70 years

Light load: 120 x 0.881917 = 105.83 kvar. One step leaves 55.83 kvar (0.9068), two steps leave 5.83 kvar, power factor 0.9988 lagging, so the controller stops at two.

Result: 4 x 50 kvar steps, 0.9701 at full load, 0.9988 lagging at light load, payback 1.70 years. Capacity, full-load power factor and light-load checks PASS.Resonance check FAIL: with three steps in, the bank resonates near the 11th harmonic. The tool recommends detuning even though the harmonics box is not ticked.

Example 5. Resonance near the 7th, then a detuned bank

A plant with drives draws 600 kW at 0.80 and targets 0.95 on 400 V three phase, from a 1000 kVA transformer with 6 per cent impedance. The harmonics box is ticked and the bank is fixed.

Active power
600 kW
Power factor
0.80 to 0.95
Transformer
1000 kVA, 6%
Harmonics
Ticked

Required: 600 x 0.75 minus 600 x 0.328684 = 450.00 minus 197.21 = 252.79 kvar, standard bank 300 kvar

Fault level: 1000 kVA / 0.06 = 16.67 MVA

Resonance: square root of (16,667 / 300) = 7.45, which is 7.45 x 50 = 372.68 Hz

Distance from the 7th: (7.45 minus 7) / 7 = 6.48 per cent, inside the 10 per cent screening margin

Add a 7 per cent reactor: tuning order 1 / square root of 0.07 = 3.78, which is 189 Hz, below the 5th harmonic at 250 Hz

Capacitor voltage with the reactor: 400 / (1 minus 0.07) = 430.11 V

Without a reactor: resonance check FAIL near the 7th harmonic.With a 7 per cent reactor: tuned to h 3.78 (189 Hz), check PASS.Specify capacitors rated above 430 V, with margin for harmonic voltage, and confirm the design with a harmonic study.

Power Factor Correction Guide for AS/NZS 61000.3.100

Power factor correction is the process of adding capacitors (or other reactive compensation equipment) to an electrical installation to reduce the reactive power drawn from the supply network. In Australia, supply authorities penalise sites that operate with a power factor below 0.90 through demand charges on the excess kVA. For industrial and commercial sites with significant motor loads, power factor correction is one of the most cost-effective electrical upgrades available, often paying for itself within 12 to 18 months through reduced electricity bills.

This calculator determines the capacitor bank size (in kVAR) needed to raise an existing power factor to a target value. Enter your site's real power consumption, current power factor, and desired target. The calculator computes the required reactive compensation and shows the reduction in apparent power (kVA) and line current that results from the correction.

Key concepts

  • Real, reactive, and apparent power. Real power (kW) does useful work. Reactive power (kVAR) sustains the magnetic fields in motors and transformers but performs no useful work. Apparent power (kVA) is the vector sum of real and reactive power, and it is what the supply network must deliver. Power factor is the ratio of kW to kVA. A power factor of 0.80 means only 80% of the apparent power is doing useful work.
  • Why low power factor costs money. The supply authority sizes transformers, cables, and switchgear based on kVA, not kW. A site drawing 200 kW at 0.70 power factor requires 286 kVA from the network, while the same 200 kW at 0.95 power factor only requires 211 kVA. The extra 75 kVA wastes network capacity and increases I squared R losses in cables. Most Australian tariffs charge a demand penalty when power factor falls below 0.90.
  • Capacitor correction principle. Capacitors generate leading reactive power that cancels the lagging reactive power drawn by inductive loads. The net reactive power seen by the supply decreases, which reduces apparent power and improves the power factor. Capacitors can be installed at the main switchboard (bulk correction) or at individual motor starters (point-of-load correction).
  • Harmonic resonance risk. A capacitor bank and the supply transformer inductance form a parallel resonant circuit. If the resonant frequency aligns with a harmonic present on the network (commonly the 5th harmonic at 250 Hz), harmonic currents can amplify and damage equipment. Detuned reactors, rated at 7% or 12.5% impedance, are installed in series with capacitors to shift the resonant frequency below the lowest significant harmonic.

Common scenarios

  • Manufacturing facility with motor loads. A factory running multiple induction motors typically has a natural power factor between 0.65 and 0.80. Installing a bulk capacitor bank at the main switchboard to correct to 0.95 reduces the site's kVA demand, lowers the electricity bill, and frees up capacity on the existing transformer for future loads. An automatic power factor correction (APFC) panel is preferred because the motor load varies throughout the day.
  • Commercial building HVAC systems. Large air-handling units and chiller compressors are inductive loads that pull the building's power factor down during peak cooling periods. Seasonal load variation makes fixed capacitor banks unsuitable because they can overcorrect during light-load periods (leading to a leading power factor, which can cause voltage rise). An APFC system with multiple switched stages is the standard solution for these installations.
  • Transformer capacity recovery. A site with a fully loaded 1000 kVA transformer at 0.80 power factor is drawing 800 kW. Correcting to 0.95 reduces the apparent demand to 842 kVA, freeing approximately 158 kVA of transformer capacity. This can defer or eliminate the need for an expensive transformer upgrade when adding new loads to the site.
Disclaimer: Verify capacitor sizing and switching scheme with a qualified electrical engineer. Resonance with system harmonics requires further analysis.

Common questions

What is power factor and why does it matter?+

Power factor is the ratio of real power (kW) to apparent power (kVA). When inductive loads like motors draw reactive power, the power factor drops below 1.0. Low power factor increases the current on cables and transformers, causes higher energy losses, and triggers demand penalties from the supply authority. Most tariffs penalise sites with power factor below 0.90.

How do I calculate the capacitor size needed for correction?+

Q_remove = P times (tan(phi_old) minus tan(phi_new)), where P is real power in kW, phi_old is arccos of current PF, phi_new is arccos of target PF. For 200 kW at 0.75 PF targeting 0.95: Q_remove = 200 times (0.882 minus 0.329) = 110.6 kVAR. Select the next standard capacitor bank rating.

Can power factor correction cause harmonic resonance?+

Yes. A capacitor bank and the supply transformer inductance form a resonant circuit. If the resonant frequency matches a harmonic (typically 5th at 250 Hz), harmonic currents amplify and can damage equipment. Detuned reactors (7 percent or 12.5 percent impedance) prevent this by shifting resonance below the lowest harmonic.

What is the difference between fixed and automatic correction?+

A fixed capacitor bank provides constant reactive power. An automatic system (APFC) uses a relay to switch capacitor steps in and out based on real-time power factor. APFC avoids overcorrection at light load (which causes leading power factor) and undercorrection at heavy load. Use APFC for variable-load sites.

What power factor does the supply authority require?+

Most Australian distributors require a minimum power factor of 0.90. Sites below this threshold pay a demand penalty based on the excess kVA. Many industrial sites target 0.95 to maximise savings and provide margin. The exact penalty structure varies by distributor and tariff class.

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