Generator Fault Current Calculator
Generator short circuit current at 10 ms, 250 ms and steady state, peak, earth fault, and whether the MCB trips on generator supply.
Inputs
Nameplate apparent power rating
Line to line, for example 415 or 400
Usually 0.8 for a standby set
Datasheet, typically 10 to 20 percent. Sets the first 10 ms
Datasheet, typically 15 to 30 percent. Sets about 250 ms
Datasheet, typically 200 to 350 percent. Sets the steady state
1 to 125 A
Multiples behind AS/NZS 3000 Table 8.1
Use phase-to-earth for a single phase final subcircuit
>Cable to the fault point
Zero puts the fault at the generator terminals
Cable Material
Return path for the phase-to-earth fault
Whole number, 1 to 12
>Advanced generator data
1.05 for LV with a +6 percent tolerance, 1.10 otherwise. 1.0 with KG off gives the simple method
X''d / Ra. Blank uses the IEC fictitious resistance (0.15 x Xd'' at LV)
Overrides the X/R when both are entered
Blank uses 0.5 (indicative, alternators 0.1 to 0.7)
PMG, AREP or booster, for example 3. Blank uses Xd with no-load excitation
How long the support holds, from the datasheet
Results
Initial Symmetrical Fault Current, Three-Phase
1.229
kA
8.83 x rated current at the terminals
| Fault | 10 ms | 250 ms | Steady state |
|---|---|---|---|
| Three-phase | 1229 A | 776 A | 56 A |
| Phase-to-phase | 1064 A | 824 A | 92 A |
| Phase-to-earth | 1468 A | 1192 A | 156 A |
Checks
- PassMCB trips magnetically at 10 ms (sub-transient, three-phase): 1229 A (min 240)
AS/NZS 3000:2018 Table 8.1
- PassMCB trips magnetically at 250 ms (transient, three-phase): 776 A (min 240)
AS/NZS 3000:2018 Table 8.1
The sustained three-phase current of 56 A is below the magnetic trip. If the MCB does not trip in the first 250 ms, it will not trip magnetically at all.
Without excitation support the steady state fault current (56 A) is below rated current (139 A). Enter the support multiple from the alternator datasheet if the set has a PMG, AREP or current booster.
Show the working
| Step | Working | Result | Reference |
|---|---|---|---|
| Rated current and base impedance | IrG = 100000 / (sqrt(3) x 415) = 139.1 A. Zbase = 415^2 / 100000 = 1.72225 ohm | 139.1 A | IEC 60909-0:2016 6.6.1 |
| Reactances in ohms | X''d = 0.12 x 1.72225 = 206.670 mohm. X'd = 0.2 x 1.72225 = 344.450 mohm. Xd = 2.5 x 1.72225 = 4305.625 mohm | 206.670 / 344.450 / 4305.625 mohm | IEC 60909-0:2016 6.6.1 |
| Generator resistance | IEC 60909 fictitious resistance for UrG <= 1 kV: RG = 0.15 x X''d = 0.15 x 206.670 = 31.000 mohm | 31.000 mohm | IEC 60909-0:2016 6.6.1 |
| Correction factor KG | KG = (Un / UrG) x c / (1 + x''d x sin(phi)) = 1 x 1.05 / (1 + 0.12 x 0.6000) = 0.9795 (sin(phi) = sqrt(1 - 0.8^2) = 0.6000). Transient (extension, indicative): K' = 1.05 / (1 + 0.2 x 0.6000) = 0.9375. Steady state uses no-load excitation E0 = 1 pu, K = c = 1.05 | 0.9795 | IEC 60909-0:2016 6.6.1 |
| Initial symmetrical (sub-transient) three-phase current I''k3 | Z = KG x (RG + jX''d) = 0.9795 x (31.000 + j206.670) = 30.364 + j202.429 mohm, |Z| = 204.693 mohm. I''k3 = c x U0 / |Z| = 1.05 x 239.6 / 0.204693 = 1229 A, 8.83 x IrG | 1.229 kA | IEC 60909-0:2016 7.2 |
| Peak short-circuit current ip | R / X = 30.364 / 202.429 = 0.1500. kappa = 1.02 + 0.98 x e^(-3 x 0.1500) = 1.6449. ip = 1.6449 x 1.4142 x 1229 = 2859 A | 2.859 kA | IEC 60909-0:2016 8.1 |
| Transient three-phase current I'k (about 250 ms) | Z = 0.9375 x (31.000 + j344.450) = 29.063 + j322.922 mohm, |Z| = 324.227 mohm. I'k = 1.05 x 239.6 / 0.324227 = 776 A, 5.58 x IrG | 0.776 kA | IEC 60909-0:2016 6.6.1 (method extended to Xd', indicative) |
| Steady state three-phase current from Xd | No-load excitation E0 = 1 pu behind Xd (indicative): Z = 1.05 x (31.000 + j4305.625) = 32.551 + j4520.906 mohm. Ik = 1.05 x 239.6 / 4.521023 = 56 A, 0.40 x IrG. A shunt excited set without support can collapse below this | 0.056 kA | IEC 60909-0:2016 11 |
| Phase-to-phase current I''k2 | I''k2 = c x U / |Z1 + Z2| with Z2 = Z1 at the sub-transient step = 1.05 x 415 / 0.409387 = 1064 A (sqrt(3)/2 of I''k3). Later steps keep Z2 at the sub-transient value: transient 824 A, steady state 92 A | 1.064 kA | IEC 60909-0:2016 7.3 |
| Phase-to-earth current I''k1 (indicative) | Solidly earthed star point assumed. Z0 = KG x (RG + j0.5 x X''d) = 30.364 + j101.214 mohm (X0 = 0.5 x X''d and R0 = RG assumed, indicative; alternators run about 0.1 to 0.7). Z1 + Z2 + Z0 = 91.093 + j506.072 mohm, |Z| = 514.205 mohm. I''k1 = 3 x c x U0 / |Z| = 3 x 1.05 x 239.6 / 0.514205 = 1468 A. Transient 1192 A, steady state 156 A | 1.468 kA | IEC 60909-0:2016 7.5 |
| MCB magnetic trip current | Curve C: 7.5 x 32 A = 240 A, the multiple Table 8.1 is based on. Checked against the three-phase current at 10 ms (1229 A) and 250 ms (776 A) | 240 A | AS/NZS 3000:2018 Table 8.1 |
Standards referenced
- IEC 60909-0:2016 Table 1. Voltage factor c: c_max 1.05 for LV systems with a +6 percent tolerance, 1.10 otherwise
- IEC 60909-0:2016 Clause 6.6.1. Synchronous generators: KG = (Un / UrG) x c_max / (1 + x''d sin(phi_rG)), fictitious resistance RG 0.05, 0.07 or 0.15 x X''d
- IEC 60909-0:2016 Clause 7.2. Three-phase initial symmetrical short-circuit current I''k
- IEC 60909-0:2016 Clause 7.3. Line-to-line short-circuit current, c Un / |Z1 + Z2|
- IEC 60909-0:2016 Clause 7.5. Line-to-earth short-circuit current, sqrt(3) c Un / |Z1 + Z2 + Z0|
- IEC 60909-0:2016 Clause 8.1. Peak short-circuit current, kappa = 1.02 + 0.98 e^(-3R/X)
- IEC 60909-0:2016 Clause 11. Steady-state short-circuit current depends on the excitation; the transient and supported values here are indicative extensions
- AS/NZS 3000:2018 Table 8.1. Maximum earth fault-loop impedance, based on MCB trip currents of 4, 7.5 and 12.5 x In for curves B, C and D
- AS/NZS 3000:2018 Clause 7.3. Electricity generation systems: generating sets, protection and earthing
- IEC 60898-1. MCB instantaneous trip bands: B 3 to 5, C 5 to 10, D 10 to 20 x In
- AS/NZS 3008.1.1:2009 Table 35. Cable a.c. resistance Rc, multicore, 75 C column, same values as 2017 (2025 Table 4.7(A))
- AS/NZS 3008.1.1:2009 Table 30. Cable reactance Xc at 50 Hz, multicore, same values as 2017 (2025 Table 4.1(B))
Where a lookup value is marked indicative, it has not been transcribed from the current edition of the standard. Check results against your own copy before relying on them for design.
Parameters
Every field on the form, what it does to the answer, and what it accepts. The six generator fields are required; everything else is optional and has a stated default.
- Generator ratingkVA, 1 to 1,000,000
- Nameplate apparent power. Sets the rated current and the base impedance, which is the rated voltage squared divided by the rating. Every reactance is a percentage of that base, so a larger set with the same percentages has proportionally more fault current.
- Rated voltagevolts line to line, 100 to 33,000
- Taken as both the generator rated voltage and the system nominal voltage, so the IEC ratio Un / UrG is 1.
- Rated power factor0.1 to 1
- Used only in the correction factor KG, through sin(phi). The correction assumes the set was running at rated load and this power factor before the fault. At 1.0, KG equals the voltage factor c.
- Sub-transient reactance Xd''percent, 1 to 50
- From the alternator datasheet. Sets the initial symmetrical current, the peak current and the 10 ms MCB check. Must not exceed the transient reactance.
- Transient reactance Xd'percent, 1 to 100
- Sets the current at about 250 ms and the 250 ms MCB check. Must not exceed the synchronous reactance.
- Synchronous reactance Xdpercent, 20 to 1,000
- Sets the steady state current when no excitation support is entered. At 250 percent the steady state is about 0.4 times rated current, which is why it rarely trips anything.
- MCB checkrating 1 to 125 A, curve B, C or D, fault type
- When ticked, the calculator compares the fault current at 10 ms and at 250 ms with the magnetic trip current of the MCB: 4, 7.5 or 12.5 times the rating for curves B, C and D, the multiples behind AS/NZS 3000 Table 8.1. The fault type picks which current is compared. Use phase-to-earth for a final subcircuit, because that is the fault automatic disconnection relies on.
- Cable length, size, material and runsmetres, mm2, copper or aluminium, 1 to 12
- The cable from the generator to the fault point. Zero length puts the fault at the terminals. Resistance comes from AS/NZS 3008.1.1 Table 35 (multicore, 75 degree column, copper or aluminium) and reactance from the multicore PVC column of Table 30, the same tables the cable sizing calculator uses. Parallel runs divide the active and earth impedance.
- Earth conductor sizemm2, optional
- Return path for the phase-to-earth fault, one per run. Defaults to the active size. A reduced earth adds 3 times its impedance to the zero sequence path and is often what fails the earth fault check.
Advanced generator data
- Apply the correction factor KGon by default
- KG = c / (1 + x''d sin(phi)) multiplies the generator impedances, as IEC 60909-0 Clause 6.6.1 sets out. Turn it off and set c to 1.0 to get the simple per unit method, rated current divided by the per unit impedance.
- Voltage factor c1.0 to 1.1, default 1.05
- IEC 60909-0 Table 1 gives c_max 1.05 for low voltage systems with a plus 6 percent tolerance and 1.10 otherwise. With KG on and no cable, c cancels out of the terminal current; it matters once a cable is in the loop.
- X/R ratio1 to 100, optional
- Sets the generator resistance as X''d divided by this ratio. Blank uses the IEC fictitious resistance: 0.15 X''d at 1 kV and below, 0.07 X''d above 1 kV under 100 MVA, 0.05 X''d at 100 MVA and over. The resistance drives the peak factor kappa.
- Armature resistance Rapercent, 0.01 to 20, optional
- The real stator resistance from the datasheet. Takes precedence over the X/R ratio when both are entered, with a warning.
- Zero-sequence ratio X0 / Xd''0.05 to 3, default 0.5
- Zero sequence reactance as a fraction of X''d. Alternators sit at about 0.1 to 0.7, so 0.5 is indicative. R0 is taken as the generator resistance. A lower ratio raises the phase-to-earth current at the terminals.
- Sustained current supportmultiple of rated current, 0.5 to 10, optional
- For a set with a PMG, AREP or current booster. Replaces the steady state value with this multiple of rated current, capped at the transient value for each fault type. The support duration field (default 10 s) only labels the working.
Assumptions and limits
What the tool assumes
- Sub-transient current follows IEC 60909-0: I''k = c Un / (sqrt(3) |KG ZG + Zcable|), with ZG = RG + jX''d. The generator is the only source; there is no grid or motor contribution.
- The transient current reuses the same form with X'd and a correction K' = c / (1 + x'd sin(phi)). IEC 60909 does not define this; it is an extension using the same rated load assumption as KG, and it is indicative.
- Without excitation support, the steady state uses no-load excitation, 1 per unit behind Xd. A shunt excited set can collapse below this, and a set with a large field forcing ceiling can hold more. Enter the datasheet support multiple where there is one.
- Phase-to-phase uses c Un / |Z1 + Z2|, and phase-to-earth uses 3 c U0 / |Z1 + Z2 + Z0|. The negative sequence impedance stays at the sub-transient value at every time step, so the phase-to-phase current decays more slowly than the three-phase current.
- The phase-to-earth figure assumes a solidly earthed star point at the generator, an X0 / X''d ratio of 0.5 unless entered, and the earth conductor as the only return path. It is indicative.
- The MCB trip current is the Table 8.1 basis (4, 7.5 or 12.5 times In). IEC 60898-1 allows a curve C MCB to need up to 10 times In, so the tool warns when the current clears the Table 8.1 figure but not the upper limit.
- Cable resistance and reactance are AS/NZS 3008.1.1:2009 Table 35 and Table 30 values (same as 2017), shared with the cable sizing calculator, at the 75 degree column, not end of fault temperature.
What it does not do
- No time constants. Currents are shown at three fixed points, not as a decrement curve. Use the manufacturer decrement curve for protection grading.
- No paralleled sets, no grid parallel operation and no inverter based sources. An inverter limits its fault current to about 1.1 to 2 times rated, which this does not model.
- No IEC 60909 minimum fault calculation with c_min and hot conductor resistance. The figures are closer to a maximum.
- No RCD check. On a small set where the MCB will not trip magnetically, an RCD is often the practical answer.
Treat the output as an indicative fault level. Check it against IEC 60909-0, AS/NZS 3000 Clause 7.3 and the alternator data, and have it signed off by whoever is responsible for the installation.
Worked examples
Three examples on the same arithmetic the calculator runs, with the default voltage factor c = 1.05 and KG applied. Currents are rounded at the end; intermediate figures carry more places.
Example 1. 100 kVA standby set, fault at the terminals, C 32 A
A 100 kVA, 415 V, 0.8 power factor set with Xd'' 12, Xd' 20 and Xd 250 percent, and no excitation support. Does a 32 A curve C MCB at the generator trip magnetically on a three-phase fault?
Inputs
- Rating 100 kVA, 415 V, power factor 0.8
- Xd'' 12 percent, Xd' 20 percent, Xd 250 percent
- No cable, MCB 32 A curve C, three-phase fault
Working
- Rated current = 100,000 / (1.732 x 415) = 139.1 A. Base impedance = 415 squared / 100,000 = 1.72225 ohms
- X''d = 0.12 x 1.72225 = 0.20667 ohms. RG = 0.15 x 0.20667 = 0.03100 ohms (fictitious, 1 kV and below)
- KG = 1.05 / (1 + 0.12 x 0.6) = 1.05 / 1.072 = 0.9795
- |ZG| = sqrt(0.03100 squared + 0.20667 squared) = 0.20898 ohms; KG x |ZG| = 0.20469 ohms
- I''k = 1.05 x 239.6 / 0.20469 = 1,229 A, 8.83 times rated current
- Peak: R / X = 0.15, kappa = 1.02 + 0.98 x e^(-0.45) = 1.6449, ip = 1.6449 x 1.4142 x 1,229 = 2,859 A
- Transient: K' = 1.05 / (1 + 0.2 x 0.6) = 0.9375, |Z'| = sqrt(0.03100 squared + 0.34445 squared) = 0.34584, I'k = 251.6 / (0.9375 x 0.34584) = 776 A
- Steady state: 239.6 / sqrt(0.03100 squared + 4.30563 squared) = 239.6 / 4.30574 = 55.6 A, 0.40 times rated current
- MCB magnetic trip = 7.5 x 32 = 240 A. 1,229 A at 10 ms and 776 A at 250 ms both exceed it
Pass: Both checks pass. The tool still warns that the steady state of 56 A is below the 240 A trip and below rated current, so if the fault is not cleared in the first quarter second it will not be cleared magnetically at all.
Example 2. Same set, 40 m of 6 mm2 with a 2.5 mm2 earth, earth fault
A single phase final subcircuit off the same set: 40 m of 6 mm2 copper actives with a 2.5 mm2 earth, protected by a 32 A curve C MCB. The check uses the phase-to-earth fault.
Inputs
- Generator as Example 1
- Cable 40 m, 6 mm2 copper, earth 2.5 mm2, 1 run
- MCB 32 A curve C, phase-to-earth fault
Working
- Table 35 (75 degree column) and Table 30: active = 3.75 x 0.04 + j0.0967 x 0.04 = 0.1500 + j0.0039 ohms. Earth = 9.01 x 0.04 + j0.102 x 0.04 = 0.3604 + j0.0041 ohms
- Z1 = Z2 = KG x (0.03100 + j0.20667) + active = 0.03036 + j0.20243 + 0.1500 + j0.0039 = 0.18036 + j0.20630 ohms
- Z0 = KG x (0.03100 + j0.5 x 0.20667) + active + 3 x earth = 0.03036 + j0.10121 + 0.1500 + j0.0039 + 1.0812 + j0.0122 = 1.26156 + j0.11732 ohms
- Z1 + Z2 + Z0 = 1.62229 + j0.52992 ohms, magnitude 1.70665 ohms
- I''k1 = 3 x 1.05 x 239.6 / 1.70665 = 754.7 / 1.70665 = 442 A
- At 250 ms, Z1 uses the transient value 0.9375 x (0.03100 + j0.34445) + active = 0.17906 + j0.32679 ohms, giving 432 A
- Three-phase at the same point for comparison: 1.05 x 239.6 / |0.18036 + j0.20630| = 251.6 / 0.27402 = 918 A
- MCB magnetic trip = 240 A. 442 A and 432 A both exceed it
Pass: Both checks pass, but the earth fault is less than half the three-phase fault at the same point because the 2.5 mm2 earth counts three times in the zero sequence path. The sustained earth fault of 148 A is below the trip, so the warning about the first quarter second still applies.
Example 3. 20 kVA portable set, 30 m of 4 mm2, earth fault on a C 32 A
A 20 kVA, 415 V set with Xd'' 14, Xd' 22 and Xd 300 percent feeds a 32 A curve C circuit 30 m away on 4 mm2 copper with a full size earth.
Inputs
- Rating 20 kVA, 415 V, power factor 0.8
- Xd'' 14 percent, Xd' 22 percent, Xd 300 percent
- Cable 30 m, 4 mm2 copper, earth same as active
- MCB 32 A curve C, phase-to-earth fault
Working
- Rated current = 20,000 / (1.732 x 415) = 27.8 A. Base impedance = 415 squared / 20,000 = 8.61125 ohms
- X''d = 0.14 x 8.61125 = 1.20558 ohms, RG = 0.15 x 1.20558 = 0.18084 ohms, KG = 1.05 / (1 + 0.14 x 0.6) = 0.9686
- Table 35 (75 degree column) and Table 30: active and earth each = 5.61 x 0.03 + j0.102 x 0.03 = 0.1683 + j0.0031 ohms
- Z1 = Z2 = 0.17516 + j1.16776 + 0.1683 + j0.0031 = 0.34346 + j1.17082 ohms
- Z0 = 0.9686 x (0.18084 + j0.60279) + 0.1683 + j0.0031 + 3 x (0.1683 + j0.0031) = 0.84836 + j0.59612 ohms
- Z1 + Z2 + Z0 = 1.53529 + j2.93776 ohms, magnitude 3.31475 ohms
- I''k1 = 754.7 / 3.31475 = 228 A, and 196 A at 250 ms
- MCB magnetic trip = 7.5 x 32 = 240 A. 228 A is below it
Fail: Both checks fail. The MCB will not trip magnetically on this set, even in the first cycle. A 32 A curve B MCB trips at 4 x 32 = 128 A and passes both checks, or an RCD gives the earth fault protection. A 25 A curve C (187.5 A) also passes, but 228 A is under its 250 A IEC 60898-1 upper limit, so the tool warns that the trip is not guaranteed.
Generator fault current, the short version
A transformer behaves like a fixed impedance, so its fault current holds steady until the protection clears it. A generator does not. Its internal reactance rises over the first second of a fault, from the sub-transient value to the transient value and then to the synchronous value, so the current falls from several times rated to, often, less than rated. A circuit that is easily protected on mains supply can be unprotected on generator supply.
That is why the MCB check is the headline here. The fault current at 10 ms tells you whether the breaker trips at all. The current at 250 ms tells you whether it still trips if the fault develops slowly. The steady state tells you what happens if it does not: usually nothing magnetic, which leaves the thermal element and a disconnection time far beyond AS/NZS 3000 limits.
Common questions
How do I calculate generator short circuit current?+
Divide the rated current by the per unit reactance for the moment you care about. Rated current is the kVA times 1000 divided by the square root of 3 times the voltage. For a 100 kVA set at 415 V that is 139.1 A. With a sub-transient reactance of 12 percent the first cycle current is about 139.1 / 0.12 = 1159 A. IEC 60909 then adds a fictitious resistance and a correction factor KG for the voltage and loading before the fault, which gives 1229 A for a set at 0.8 power factor.
Why will my circuit breaker not trip on generator supply?+
A generator can only deliver a large fault current for a few cycles. The sub-transient current decays to the transient value by about 250 ms and then to a steady state value set by the synchronous reactance, which is often less than rated current. A C curve MCB needs 7.5 times its rating to trip magnetically. On a small set at the end of a long cable, the earth fault current can sit below that from the first cycle, and the MCB then relies on its thermal element, which is far too slow for the 0.4 s disconnection time.
What are sub-transient, transient and synchronous reactance?+
They are the alternator reactance at three points after a fault. Sub-transient Xd prime prime, typically 10 to 20 percent, applies for roughly the first 10 to 50 ms. Transient Xd prime, typically 15 to 30 percent, applies for roughly 250 ms to a second. Synchronous Xd, typically 200 to 350 percent, applies once the fault has settled. All three are on the alternator datasheet as percentages on the set rating.
What does a PMG or AREP excitation do to fault current?+
A shunt excited alternator takes its field power from its own output, so a close fault collapses the field and the current falls away. A permanent magnet generator (PMG), an auxiliary winding system (AREP) or a current booster keeps the field up and holds the fault current at a set multiple of rated current, commonly about 3 times for 10 seconds. Enter that multiple in the sustained current field to see whether the MCB trips on the held current.
Is the phase to earth fault from a generator higher than the three phase fault?+
Often, at the terminals. The zero sequence reactance of an alternator is usually only 0.1 to 0.7 times its sub-transient reactance, so with a solidly earthed star point the phase to earth current can exceed the three phase current. Down a cable it reverses quickly, because the earth conductor adds to the loop and a reduced earth adds a lot. Check the earth fault at the far end of the circuit, not at the generator.
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